a/ Ta có : \(\left|x-3\right|\ge0\)
\(\Leftrightarrow5-\left|x-3\right|\le5\)
Dấu "=" xảy ra khi :
\(\left|x-3\right|=0\Leftrightarrow x=3\)
Vậy ...
b/ \(\left|2+x\right|\ge0\)
\(15+\left|2+x\right|\ge15\)
Dấu "=" xảy ra khi :
\(\left|2+x\right|=0\Leftrightarrow x=-2\)
Vậy ...
Ta có: \(\left|x-3\right|\ge0\Rightarrow5-\left|x-3\right|\le5-0=5\)
\(\Rightarrow Max\left(5-\left|x-3\right|\right)=5\Leftrightarrow x=3\)
Ta có: \(\left|2+x\right|\ge0\Rightarrow15+\left|2+x\right|\ge15+0=15\)
\(\Rightarrow Min\left(15+\left|2+x\right|\right)=15\Leftrightarrow x=-2\)
a) Ta có:
\(\left|x-3\right|\ge0\Rightarrow5-\left|x-3\right|\le5-0=5\)
\(\Rightarrow\)GTLN của \(5-\left|x-3\right|\)là: 5 khi x = 3
b) Ta có:
\(\left|2+x\right|\ge0\)\(\Rightarrow15+\left|2+x\right|\ge15+0=15\)
\(\Rightarrow\)GTNN của \(15+\left|2+x\right|\)là: 15 khi x = -2
