Question

a, \(\dfrac{6}{xy^2}:\left(\dfrac{-2x^2}{y}\right)\)

b, \(\left(x^3-2x^2+x+18\right):\left(x+2\right)\)

Answer 1

a: \(=\dfrac{6}{xy^2}\cdot\dfrac{-y}{2x^2}=\dfrac{-6}{2x^3y}=\dfrac{-3}{x^3y}\)

b: \(=\dfrac{x^3+2x^2-4x^2-8x+9x+18}{x+2}=x^2-4x+9\)

Answer 2

\(a,\dfrac{6}{xy^2}.\left(\dfrac{-y}{2x^2}\right)=\dfrac{-6y}{2x^3y^2}=\dfrac{-3}{x^3y}\)