a: \(y+\dfrac{1}{2}\cdot\dfrac{1}{3}=\dfrac{3}{4}\)
=>\(y+\dfrac{1}{6}=\dfrac{3}{4}\)
=>\(y=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{9}{12}-\dfrac{2}{12}=\dfrac{7}{12}\)
b: \(y+\dfrac{1}{2}\cdot\dfrac{1}{5}=\dfrac{3}{10}\)
=>\(y+\dfrac{1}{10}=\dfrac{3}{10}\)
=>\(y=\dfrac{3}{10}-\dfrac{1}{10}=\dfrac{2}{10}=\dfrac{1}{5}\)
Bài 2: (đề 2) Tìm y
a) \(2\dfrac{2}{5}-y:2\dfrac{3}{4}=1\dfrac{1}{2}\) b) \(1\dfrac{1}{4}+2\dfrac{1}{5}\) x \(y=2\dfrac{3}{5}\)
c) \(2\dfrac{4}{5}-2\dfrac{1}{4}:y=\dfrac{3}{4}\) c) \(x:3\dfrac{1}{3}=2\dfrac{2}{5}+\dfrac{7}{10}\)
Bài 2 Tìm y
a) \(\dfrac{1}{2}-2xy=\dfrac{9}{20}\) b)\(\dfrac{3}{5}:\dfrac{4}{3}:y=2+\dfrac{7}{10}\) c) y + y x\(\dfrac{3}{2}-y\) x \(\dfrac{1}{2}=\dfrac{1}{10}\)
bài 3: Tìm y
a) \(\dfrac{1}{2}\) : y x \(\dfrac{3}{5}=\dfrac{4}{3}+\dfrac{3}{4}\) b) \(\dfrac{4}{3}-\dfrac{1}{2}\) x y \(=1\) c) \(\dfrac{1}{4}+y\) : \(\dfrac{1}{3}=\dfrac{5}{6}\)
Bài 3: (Đề 2) Tìm y
a) \(2\dfrac{2}{5}:\) y x \(1\dfrac{3}{4}=\dfrac{7}{8}\) b)\(3\dfrac{2}{5}:y:1\dfrac{1}{4}=2\dfrac{3}{5}\) c) \(\dfrac{12}{5}-2\dfrac{2}{5}x\) y \(=1\dfrac{1}{4}\)
bài 1:
2 : y x \(\dfrac{3}{5}\) = \(\dfrac{9}{10}\) \(\dfrac{5}{4}-\dfrac{2}{5}:\) y = 1 \(\dfrac{3}{4}x\) (\(\dfrac{7}{2}\) - y) =\(\dfrac{3}{2}\)
Tìm y
a) 3 \(\dfrac{1}{5}\) : 2\(\dfrac{1}{3}\): y = \(\dfrac{12}{7}\)
b) 3 : y x 3 \(\dfrac{1}{2}\)= \(\dfrac{2}{3}x\dfrac{3}{4}\)
c) \(3\dfrac{2}{3}-y+1\dfrac{3}{4}=2\)
Bài 6: ( Đề 1) Tìm y
a) \(3\dfrac{1}{5}:2\dfrac{1}{3}:y=\dfrac{12}{7}\) b) \(3:yx3\dfrac{1}{2}=\dfrac{2}{3}x\dfrac{3}{4}\) c) \(3\dfrac{2}{3}-y+1\dfrac{3}{4}=2\)
Tìm y
\(\dfrac{2}{5}\) X y : \(\dfrac{7}{4}=\dfrac{7}{8}\)
2\(\dfrac{2}{5}\) : y x 1\(\dfrac{1}{4}\) = 2\(\dfrac{3}{5}\)
\(\dfrac{12}{5}-1\dfrac{2}{5}x\) y = 1\(\dfrac{1}{4}\)
Bài 2 Tìm x
a) 4\(\dfrac{2}{3}:x-\dfrac{3}{5}=\dfrac{4}{3}\)
b) \(\dfrac{4}{3}+2\dfrac{1}{2}\)x \(X=2\)
c) \(X:3\dfrac{1}{3}=2\dfrac{2}{5}+\dfrac{7}{10}\)
