Quãng đường AB:
\(s_{AB}=v_{AB}\cdot t_{AB}=\left(\dfrac{\left(18\cdot1+\dfrac{57,5}{60}\right)+\left(24\cdot1+\dfrac{50}{60}\right)}{1+\dfrac{57,5}{60}+1+\dfrac{50}{60}}\right)\cdot\left(1+\dfrac{57,5}{60}+1+\dfrac{50}{60}\right)=79,25\left(km\right)\)