Question

a) 

b) 

c) 

d) 
                                                         GIÚP TỚ NHE

Answer 1

a: \(\dfrac{1}{3}:x=2\dfrac{2}{3}:\left(-0,3\right)\)

=>\(\dfrac{1}{3}:x=\dfrac{8}{3}:\dfrac{-3}{10}=-\dfrac{80}{9}\)

=>\(x=-\dfrac{1}{3}:\dfrac{80}{9}=-\dfrac{1}{3}\cdot\dfrac{9}{80}=-\dfrac{3}{80}\)

b: \(3^{2x}-2\cdot3^5=3^5\)

=>\(3^{2x}=3^5+2\cdot3^5=3\cdot3^5=3^6\)

=>2x=6

=>x=3

c: \(2x-\sqrt{1,69}=\sqrt{1,21}\)

=>2x-1,3=1,1

=>2x=1,3+1,1=2,4

=>x=2,4/2=1,2

d: \(\left|x+\dfrac{1}{3}\right|\cdot\left(x^2+1\right)=0\)

mà \(x^2+1>=1\forall x\)

nên \(\left|x+\dfrac{1}{3}\right|=0\)

=>\(x+\dfrac{1}{3}=0\)

=>\(x=-\dfrac{1}{3}\)

Answer 2

bạn nào giải cho tớ tớ tick cho