\(a,\dfrac{7}{6}+\dfrac{2}{5}=\dfrac{35}{30}+\dfrac{12}{30}=\dfrac{47}{30}\\ b,\dfrac{8}{12}+\dfrac{3}{4}=\dfrac{8}{12}+\dfrac{9}{12}=\dfrac{17}{12}\\ c,4+\dfrac{9}{10}=\dfrac{40}{10}+\dfrac{9}{10}=\dfrac{49}{10}\\ d,\dfrac{2}{6}+3=\dfrac{1}{3}+3=\dfrac{1}{3}+\dfrac{9}{3}=\dfrac{10}{3}\)
\(\dfrac{7}{6}+\dfrac{2}{5}=\dfrac{35}{30}+\dfrac{12}{30}=\dfrac{35+12}{30}=\dfrac{47}{30}\)
\(\dfrac{8}{12}+\dfrac{3}{4}=\dfrac{8}{12}+\dfrac{9}{12}=\dfrac{8+9}{12}=\dfrac{15}{12}=\dfrac{5}{4}\)
\(4+\dfrac{9}{10}=\dfrac{40}{10}+\dfrac{9}{10}=\dfrac{40+9}{10}=\dfrac{49}{10}\)
\(\dfrac{2}{6}+3=\dfrac{1}{3}+\dfrac{3}{1}=\dfrac{1}{3}+\dfrac{9}{3}=\dfrac{1+9}{3}=\dfrac{10}{3}\)
a, 7/6 + 2/5 = 47/30
b, 8/12 + 3/4 = 17/12
c, 4 + 9/10 = 49/10
d, 2/6 + 3 = 10/3