a: 2x-2,5=4,1
=>2x=2,5+4,1=6,6
=>x=6,6:2=3,3
b: \(x:\dfrac{1}{3}=\dfrac{7}{6}+\dfrac{5}{3}\)
=>\(x:\dfrac{1}{3}=\dfrac{7}{6}+\dfrac{10}{6}=\dfrac{17}{6}\)
=>\(x=\dfrac{17}{6}\cdot\dfrac{1}{3}=\dfrac{17}{18}\)
c: \(12\left(x-2\right)^2=3\)
=>\(\left(x-2\right)^2=\dfrac{1}{4}\)
=>\(\left[{}\begin{matrix}x-2=\dfrac{1}{2}\\x-2=-\dfrac{1}{2}\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=\dfrac{3}{2}\end{matrix}\right.\)
`a, 2x - 2,5 = 4,1`
`=> 2x = 4,1 + 2,5`
`=> 2x = 6,6`
`=> x = 6,6 : 2`
`=> x = 3,3`
Vậy: `x= 3,3`
`b, x:1/3 + 7/6 = 5/3`
`=> x: 1/3 = 5/3 - 7/6`
`=> x :1/3 = 1/2`
`=> x = 1/2 . 1/3`
`=> x = 1/6`
Vậy: `x=1/6`
`c, 12(x-2)^2=3`
`=> (x-2)^2 = 3 : 12`
`=> (x-2)^2 = 1/4`
`=> (x-2)^2 = (+-1/2)^2`
`=> x - 2 = 1/2` hay `x - 2 = -1/2`
`=> x = 1/2 + 2` hay `x = -1/2+2`
`=> x = 5/2` hay `x = 3/2`
Vậy: `x = {5/2 ; 3/2}`
