\(A=1\dfrac{1}{2}\times1\dfrac{1}{3}\times1\dfrac{1}{4}\times....\times1\dfrac{1}{2020}\times1\dfrac{1}{2021}\\ =\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\times\dfrac{6}{5}\times....\times\dfrac{2022}{2021}\\ =\dfrac{3\times4\times5\times6\times.....\times2022}{2\times3\times4\times5\times....\times2021}\\ =\dfrac{2022}{2}=1011\)
Tìm A biết: A\(\times\)(1-\(\dfrac{1}{4}\))\(\times\)(1-\(\dfrac{1}{9}\))\(\times\)(1-\(\dfrac{1}{16}\))\(\times\)(1-\(\dfrac{1}{25}\))=1\(\dfrac{3}{5}\)
\(\dfrac{15}{16}\div\dfrac{5}{8}\times\dfrac{3}{4}\)
\(\dfrac{21}{4}\times\dfrac{16}{14}\times\dfrac{1}{2}\times\dfrac{8}{3}\)
Tính giá trị biểu thức: A=29\(\dfrac{1}{2}\)\(\times\)\(\dfrac{2}{3}\)+39\(\dfrac{1}{3}\)\(\times\)\(\dfrac{3}{4}\)+\(\dfrac{5}{6}\)
(Nhớ rút gọn đến tối giản, trình bày theo cách của học sinh lớp 5)
\(3\dfrac{7}{8}\times x-2\dfrac{3}{4}=3\dfrac{6}{12}\times\dfrac{10}{8}-\dfrac{1}{3}\)
cíuuuuuu
\(3\dfrac{7}{8}\times x-2\dfrac{3}{4}=3\dfrac{6}{12}\times\dfrac{10}{8}-\dfrac{1}{3}\)
Tìm x
tính
\(3\dfrac{1}{5}\times\dfrac{10}{11}+1\dfrac{2}{11}=\)
\(5\dfrac{1}{3}:1\dfrac{2}{3}-1\dfrac{1}{5}=\)
mik cần gấp mn 1
\(\dfrac{2}{3}\times x-\dfrac{4}{7}=\dfrac{1}{8}\)
\(2\times(x-\dfrac{1}{2})=3\dfrac{1}{3}\)
\(\dfrac{12}{5}\times\dfrac{5}{9}-\dfrac{1}{3}\)
