Question

a) 1/2x+3/5x=(−3)/65
b) (2/9x−4/9)(1/3+(−4)/7:x)=0
c) (x+5)/2015+(x+6)/2014+(x+7)/2013+(x+8)/2012+(x+9)/2011=−5;
d) (x+2)/338+(x+3)/337+(x+4)/336+(x+5)/335+(x+360)/5=0.

 

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Answer 1

a: =>1,1x=-3/65

=>11/10x=-3/65

=>x=-3/65:11/10=-3/65x10/11=-6/143

b: =>2/9x-4/9=0 hoặc 1/3-4/7:x=0

=>x=2 hoặc 4/7:x=1/3

=>x=2 hoặc x=4/7:1/3=12/7

c: =>\(\left(\dfrac{x+5}{2015}+1\right)+\left(\dfrac{x+6}{2014}+1\right)+\left(\dfrac{x+7}{2013}+1\right)+\left(\dfrac{x+8}{2012}+1\right)+\left(\dfrac{x+9}{2011}+1\right)=0\)

=>x+2020=0

=>x=-2020