Question

a,-1/2 xy² x 3x³y
b ,(xy)² x (-3xy²z)
c ,(2xy) x (-1/4 x²) x y³

Answer 1

`@` `\text {Ans}`

`\downarrow`

`a,`

`-1/2xy^2*3x^3y`

`= (-1/2*3)(x*x^3)(y^2*y)`

`= -3/2x^4y^3`

`b,`

`(xy)^2*(-3xy^2z)`

`= (-3)(x^2*x)(y^2*y^2)(z)`

`= -3x^3y^4z`

`c,`

`(2xy)*(-1/4x^2)*y^3`

`= (2*-1/4)(x*x^2)(y*y^3)`

`= -1/2x^3y^4`

Answer 2

a: =-1/2*3*x^3*x*y^2*y=-3/2x^4y^3

b: =x^2y^2*(-3)xy^2z=-3x^3y^4z

c: =2*(-1/4)*xy*x^2*y^3=-1/2x^3y^4

Answer 3

dấu x mà bạn cách là x thì giải thế này, còn không thì nói

a)

\(=\left(-\dfrac{1}{2}.3\right)\left(x.x^3\right).\left(y^2.y\right)=-\dfrac{3}{2}x^4y^3\)

b)

\(=-3.\left(x^2.x.x\right).\left(y^2.y^2\right).z=-3x^4y^4z\)

c)

\(=\left(2.\dfrac{-1}{4}\right).\left(x.x.x^2.x\right).\left(y.y^3\right)=-\dfrac{1}{2}.x^5.y^4\)