a. ĐKXĐ: \(x\ne1\)
\(\dfrac{11x-4}{x-1}+\dfrac{10x+4}{2-2x}=\dfrac{2\cdot\left(11x-4\right)}{2\cdot\left(x-1\right)}-\dfrac{10x+4}{2x-2}\)
\(=\dfrac{22x-8}{2\left(x-1\right)}-\dfrac{10x+4}{2\left(x-1\right)}\)\(=\dfrac{22x-8-10x-4}{2\left(x-1\right)}\)
\(=\dfrac{12x-12}{2\left(x-1\right)}\)\(=\dfrac{12\left(x-1\right)}{2\left(x-1\right)}=6\)
b. ĐKXĐ: \(x\ne-2;x\ne\dfrac{1}{2}\)
\(\dfrac{1}{x+2}+\dfrac{5}{2x^2+3x-2}=\dfrac{2x-1}{\left(2x-1\right)\left(x+2\right)}+\dfrac{5}{\left(2x-1\right)\left(x+2\right)}\)
\(=\dfrac{2x-1+5}{\left(2x-1\right)\left(x+2\right)}=\dfrac{2x+4}{\left(2x-1\right)\left(x+2\right)}\)
\(=\dfrac{2\left(x+2\right)}{\left(2x-1\right)\left(x+2\right)}=\dfrac{2}{2x-1}\)
\(\text{#}Toru\)
