Question

a) -1 1/3 -x=2,5

b) 1/3 : x -20%=16/-32

c) ( 3x/7 + 1 ) : (-4) =-1/28 

Answer 1

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Answer 2

a) Ta có: \(-1\dfrac{1}{3}-x=2.5\)

\(\Leftrightarrow\dfrac{-4}{3}-x=\dfrac{5}{2}\)

hay \(x=\dfrac{-4}{3}-\dfrac{5}{2}=\dfrac{-8}{6}-\dfrac{15}{6}=\dfrac{-23}{6}\)

b) Ta có: \(\dfrac{1}{3}:x-20\%=\dfrac{16}{-32}\)

\(\Leftrightarrow\dfrac{1}{3}:x=\dfrac{-1}{2}+\dfrac{1}{5}=\dfrac{-3}{10}\)

hay \(x=\dfrac{1}{3}:\dfrac{-3}{10}=\dfrac{1}{3}\cdot\dfrac{10}{-3}=\dfrac{-10}{9}\)

c) Ta có: \(\left(\dfrac{3x}{7}+1\right):\left(-4\right)=\dfrac{-1}{28}\)

\(\Leftrightarrow\dfrac{3}{7}x+1=\dfrac{1}{7}\)

\(\Leftrightarrow x\cdot\dfrac{3}{7}=\dfrac{1}{7}-1=\dfrac{-6}{7}\)

hay x=-2

Answer 3

a) Ta có: ⇔−43−x=52⇔−43−x=52

hay 13:x−20%=16−3213:x−20%=16−32

x=13:−310=13⋅10−3=−109x=13:−310=13⋅10−3=−109

c) Ta có: ⇔37x+1=17⇔37x+1=17