\(8x\left(x-3\right)-\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(8x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\8x-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{8}\end{matrix}\right.\)
Vậy: \(S=\left\{3;\dfrac{1}{8}\right\}\)
\(8x\left(x-3\right)-\left(x-3\right)=0\\ \Leftrightarrow\left(x-3\right)\left(8x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-3=0\\8x-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{8}\end{matrix}\right.\\ \)
Vậy tập nghiệm của phương trình là \(S=\left\{3;\dfrac{1}{8}\right\}\)
\(\Leftrightarrow\left(x-3\right)\left(8x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{8}\end{matrix}\right.\)