Question

8^7. 9^21/ 6^20.27^7

Answer 1

\(\dfrac{8^7.9^{21}}{6^{20}.27^7}=\dfrac{\left(2^3\right)^7.\left(3^2\right)^{21}}{\left(2.3\right)^{20}.\left(3^3\right)^7}=\dfrac{2^{21}.3^{42}}{2^{20}.3^{20}.3^{21}}=2.3=6\)

Answer 2

\(\dfrac{8^7\cdot9^{21}}{6^{20}\cdot27^7}=\dfrac{2^{21}\cdot3^{42}}{2^{20}\cdot3^{20}\cdot3^{21}}=2\cdot3=6\)