Bài 1:
a) \(\frac{2}{3}-\frac{1}{3}\left(x-\frac{3}{2}\right)-\frac{1}{2}\left(2x+1\right)=5\)
\(\frac{2}{3}-\frac{1}{3}x+\frac{1}{2}-x-\frac{1}{2}=5\)
\(\frac{2}{3}-\frac{4}{3}x=5\)
\(\frac{4}{3}x=-\frac{13}{3}\)
\(x=-\frac{13}{4}\)
b) \(\left(x+\frac{1}{2}\right)\left(x-\frac{3}{4}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\x-\frac{3}{4}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{3}{4}\end{cases}}}\)
Vậy x=-1/2 hoặc x=3/4
Bài 2:
\(\frac{1}{3}^{-1}-\left(-\frac{6}{7}\right)^0+\left(-\frac{1}{2}\right)^2:2\)
\(=3-1+\frac{1}{2}\)
\(=\frac{5}{2}\)
a) 2/3 —1/3.(x—3/2)—1/2.(2x+1)=
(1/3x - 1/3.3/2) - (1/2.2x + 1/2.1) = 2/3 - 5
1/3x - 1/2 - x - 1/2 = -13/3
(1/3x - x) + (-1/2 - 1/2) = -13/3
-2/3x - 1 = -13/3
-2/3x = -13/3 + 1
-2/3x = -10/3
x = -10/3 + 2/3
x = -8/3
b )(x+1/2).(x—3/4)=0
=> x + 1/2 = 0 hoặc x - 3/4 = 0
x = 0 - 1/2 x = 0 + 3/4
x = -1/2 x = 3/4
vậy x = -1/2 hoặc x =3/4
(1/3)^???—1 —(—6/7)^0 + (—1/2)^2 :2
