Question

-8 x ( \(-\dfrac{1}{4}\))\(^2\) + | \(-\dfrac{1}{3}\) | : \(\sqrt{\dfrac{1}{9}}\)=???

Answer 1

=-8*1/16+1/3:1/3

=-1/2+1

=1/2

Answer 2

`-8 \times (-1/4)^2 + |-1/3| \div \sqrt {1/9}`

`= -8 \times 1/16 + 1/3 \div 1/3`

`= -1/2 + 1`

`= 1/2`

Answer 3

\(-8\times\left(-\dfrac{1}{4}\right)^2+\left|-\dfrac{1}{3}\right|:\sqrt{\dfrac{1}{9}}\\ =-8\times\dfrac{1}{16}+\dfrac{1}{3}:\dfrac{1}{3}\\ =-\dfrac{8}{16}+\dfrac{1}{3}\times3\\ =-\dfrac{8}{16}+1\\ =-\dfrac{8}{16}+\dfrac{16}{16}\\ =\dfrac{8}{16}\\ =\dfrac{1}{2}\)