a: \(=7+\dfrac{1}{4}+4+\dfrac{5}{10}==11+\dfrac{3}{4}=\dfrac{47}{4}\)
b: \(=\dfrac{19}{5}:\dfrac{3}{8}=\dfrac{19}{5}\cdot\dfrac{8}{3}=\dfrac{152}{15}\)
c: \(=\dfrac{11}{4}:\dfrac{15}{8}=\dfrac{11}{4}\cdot\dfrac{8}{15}=\dfrac{88}{60}=\dfrac{22}{15}\)
d: \(=\left(3+\dfrac{3}{4}+\dfrac{1}{4}\right)\cdot2=4\cdot2=8\)