`|5x|-3x-2=0`
`<=>|5x|=3x+2(x>=-2/3)`
`+)5x=3x+2`
`<=>2x=2`
`<=>x=1(tm)``
`+)-5x=3x+2`
`<=>8x=-2`
`<=>x=-1/4(tm)`
Vậy `S={1,-1/4}`
\(\left|5x\right|-3x-2=0\)
\(\Leftrightarrow\left|5x\right|=3x+2\)
TH1: x ≥ 0
⇒ 5x = 3x + 2
⇔ x = 1 (tm)
TH2: x < 0
⇒ 5x = -3x - 2
⇔ x = -1/4 (tm)
Vậy...