=>(x+2)(x+5)=0
=>x=-2 hoặc x=-5
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Bài 2: Tìm x, biết: a) (x + 2)^2 – 2(x + 2)(x – 5) = 0. b) 2x^2 + 3x – 5 = 0. c) x + 2 ^2 x 2 + 2x^3 = 0. d) (3x-1)^2-4(x+5)^2=0
Bài 4: Tìm x: 1) x2 - 9x 0 2) x(x - 4) – x2 7 3) 3x + 2(x – 5) 5 4) 25x2 - 1 0 5) 3x(x - 2) - 5(x - 2) 0 6) 3x(x - 7) + 4(x – 7) 0 7) 4x2 – 9 0 8) 10x(x - 4) + 2x - 8 0 9) x(2x - 5) - 2x2 0 10) 2x2 – 4x 0 11) 2x(3 - 4x) + 3(4x - 3) 0 12) 2x (x – 5) – 2x2 3mọi người giúp mình vs chiều 1g mình thi rồi! cảm ơn!
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Bài 4: Tìm x:
1) x2 - 9x = 0 2) x(x - 4) – x2 = 7 3) 3x + 2(x – 5) = 5
4) 25x2 - 1 = 0 5) 3x(x - 2) - 5(x - 2) = 0 6) 3x(x - 7) + 4(x – 7) = 0
7) 4x2 – 9 = 0 8) 10x(x - 4) + 2x - 8 = 0 9) x(2x - 5) - 2x2 = 0
10) 2x2 – 4x = 0 11) 2x(3 - 4x) + 3(4x - 3) = 0 12) 2x (x – 5) – 2x2 = 3
mọi người giúp mình vs chiều 1g mình thi rồi! cảm ơn!
1) x^2-25+2(x+5)=0
2) x(x-1)+x-1=0
3) (3x-2)^2-(x+2)^2=0
4) 2(x-2)-x^2+4x-4=0
5) 2(x^2+8x+16)-x^2+4=0
Tìm x,biết
1) 3x^2 - 4x = 0
2) (x^2 - 5x) + x - 5 = 0
3) x^2 - 5x + 6 = 0
4) 5x(x-3) - x+3 = 0
5) x^2 - 2x + 5 = 0
6) x^2 + x -6 = 0
a,x+5/x-1+8/x^2-4x+3=x+1/x-3 b,x-4/x-1-x^2+3/1-x^2+5/x+1=0 c,3x/4-5=3-x/2+5x-1/6 d,(x-2)(x+2)-(x-3)(x+4)-2x+3=0 e,(x-1)^2+2(x+1)=5x+5 g,(x-3)(x+4)x=0
Tìm x
1, 2X(X-3)-(3-X)=0
2, 3X(X+5)-6(X+5)=0
3, X^4 - X^2 =0
4, X^2-2X=0
5, X(X+6)-10(X-6)=0
Các bạn giúp mk vs ạ mk cần gấp
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Tìm x, biết : a/ dfrac{1}{3}xleft(x^2-4right)0b/ xleft(x+5right)x+5c/ x^3-dfrac{1}{9}x03)^2-left(x+5right)^20e/ left(x+2right)^2-left(x-2right)left(x+2right)0f/ xleft(2x-3right)-6+4x0g/ 2left(3x-2right)^2-9x^2+40h/ x^2left(x+1right)+2xleft(x+1right)0i/ 4x^2+9x+50
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Tìm x, biết :
a/ \(\dfrac{1}{3}x\left(x^2-4\right)=0\)
b/ \(x\left(x+5\right)=x+5\)
c/ \(x^3-\dfrac{1}{9}x=0\)
3)\(^2-\left(x+5\right)^2=0\)
e/ \(\left(x+2\right)^2-\left(x-2\right)\left(x+2\right)=0\)
f/ \(x\left(2x-3\right)-6+4x=0\)
g/ \(2\left(3x-2\right)^2-9x^2+4=0\)
h/ \(x^2\left(x+1\right)+2x\left(x+1\right)=0\)
i/ \(4x^2+9x+5=0\)
b2 tìm x
a)x^2-4x-5=0
b)5x^2-9x-2=0
c)(x^2+1)-5(x^2+1)+6=0
d)(x^2+6x)-2(x+3)^2-17=0
a)(3x+1)^2-x^2+8x-16=0
b)(x+1)(x-1)^2-(x+1)(x-2)^2=0
c)(x+1)(x-3)^2=(3x+1)(2x-5)^2
đ)(x+5)(3x+2)^2=x^2(x+5)
e)x^3-8x^2+21x-18=0
f)x^4+x^2+6x-8=0
a, (x-1)^3=x-1
b, (x-2)^3=4.(x-2)
c. (x+3)^5=9.(x+5)^3
d,(x-5)^10=(5-x)^7
e, (2.x-1)^2020-(2x-1)^2018=0
f, x4-8x=0
g, x^3-16x=0
h, 4.x^2-x^4=0
i, x^4+9x^2=0
k, x^5+8x^2=0
l, 81.x^2-9x^4=0
m, 32x^5+x^10=0
n, (11-15)^2-5.(3^2-4.x^2)= -9
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