\(\dfrac{5}{a}=\dfrac{105}{189}\Leftrightarrow105.a=5.189\Leftrightarrow105.a=985\Leftrightarrow a=9\)
\(\dfrac{b}{108}=\dfrac{105}{189}\Leftrightarrow b.189=108.105\Leftrightarrow b.189=11340\Leftrightarrow b=60\)
\(\dfrac{5}{a}=\dfrac{105}{189}=\dfrac{b}{108}\)
\(\Rightarrow\left\{{}\begin{matrix}a=\dfrac{189.5}{105}=9\\b=\dfrac{105.108}{189}=60\end{matrix}\right.\)
Vậy a = 9, b = 60
Ta có: \(\dfrac{5}{a}=\dfrac{105}{189}=\dfrac{b}{108}\)
\(\Leftrightarrow\left\{{}\begin{matrix}a=\dfrac{5\cdot189}{105}=9\\b=\dfrac{108\cdot105}{189}=60\end{matrix}\right.\)