\(\dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\)
<=>\(\dfrac{x}{35}=\dfrac{4}{5}-\dfrac{5}{7}=\dfrac{28-25}{35}=\dfrac{3}{35}\)
<=>x=3
\(\dfrac{x}{35}\)=\(\dfrac{4}{5}-\dfrac{5}{7}\)
\(\dfrac{x}{35}\)=\(\dfrac{3}{35}\)
Vậy x=3
\(\dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\)
\(\dfrac{25+x}{35}=\dfrac{28}{35}\)
\(25+x=28\)
\(x=28-25\)
\(x=3\)