\(n_{Fe}=\dfrac{5,6}{56}=0,1\left(mol\right)\)
PT: \(Fe+2HCl\rightarrow FeCl_2+H_2\)
Theo PT: \(\left\{{}\begin{matrix}n_{FeCl_2}=n_{H_2}=n_{Fe}=0,1\left(mol\right)\\n_{HCl}=2n_{Fe}=0,2\left(mol\right)\end{matrix}\right.\)
a, \(V_{H_2}=0,1.24,79=2,479\left(l\right)\)
b, \(m_{FeCl_2}=0,1.127=12,7\left(g\right)\)
c, \(V_{HCl}=\dfrac{0,2}{2,5}=0,08\left(l\right)\)