Question

{5.[42:(5x3+50:10)x3:2+4]} + {35.[63:9.(5²)]}

ai trả lời nhanh mik tick

Answer 1

\(\left\{5.\left[42:\left(5.3+50:10\right).3:2+4\right]\right\}+\left\{35.\left[63:9.\left(5^2\right)\right]\right\}\\ =\left\{5.\left[42:\left(15+5\right).1,5+4\right]\right\}+\left\{35.\left(9.25\right)\right\}\\ =\left\{5.\left[42:20.1,5+4\right]\right\}+\left\{35.225\right\}\\ =\left\{5.\left[2,1.1,5+4\right]\right\}+7875\\ =\left\{5.\left[3,15+4\right]\right\}+7875\\ =\left\{5.7,15\right\}+7875\\ =35,75+7875\\ =7910,75\)

Answer 2

{5.[42:(5.3+50:10).3:2+4]}+{35.[63:9.(52)]}={5.[42:(15+5).1,5+4]}+{35.(9.25)}={5.[42:20.1,5+4]}+{35.225}={5.[2,1.1,5+4]}+7875={5.[3,15+4]}+7875={5.7,15}+7875=35,75+7875=7910,75

Answer 3

{5.[42:(5.3+50:10).3:2+4]}+{35.[63:9.(52)]}

={5.[42:(15+5).1,5+4]}+{35.(9.25)}

={5.[42:20.1,5+4]}+{35.225}

={5.[2,1.1,5+4]}+7875={5.[3,15+4]}+7875

={5.7,15}+7875

=35,75+7875

=7910,75