\(pt\Leftrightarrow\left[{}\begin{matrix}-5x=\dfrac{5}{3}\\-5x=-\dfrac{5}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=\dfrac{1}{3}\end{matrix}\right.\Leftrightarrow x=\pm\dfrac{1}{3}\)
Vậy ........
\(\left|-5x\right|=\dfrac{5}{3}\)
\(\Rightarrow\left[{}\begin{matrix}-5x=\dfrac{5}{3}\\-5x=-\dfrac{5}{3}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=\dfrac{1}{3}\end{matrix}\right.\)
Vậy \(x=\dfrac{1}{3}\) hoặc \(x=-\dfrac{1}{3}\)
Ta có: \(\left|-5x\right|=\dfrac{5}{3}\)
nên \(\left[{}\begin{matrix}-5x=\dfrac{5}{3}\\-5x=-\dfrac{5}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=\dfrac{1}{3}\end{matrix}\right.\)