Question

5-(x-6)=4(3-2x)

Answer 1

\(5-\left(x-6\right)=4\left(3-2x\right)\)

\(\Leftrightarrow5-\left(x-6\right)=12-8x\)

\(\Leftrightarrow5-\left(x-6\right)+8x=12\)

\(\Leftrightarrow5-x+6+8x=12\)

\(\Leftrightarrow7x=12-5-6\)

\(\Leftrightarrow7x=1\)

\(\Leftrightarrow x=\dfrac{1}{7}\)

Vậy \(S=\dfrac{1}{7}\)

Answer 2

5 - (x - 6) = 4(3 - 2x)

⇔ 5 - x + 6 = 12 - 8x

⇔ -x + 8x = 12 - 5 - 6

⇔ 7x = 1

⇔ x = 1/7

Vậy S = {1/7}

Answer 3

5-(x-6)=4(3-2x)

<=>5-x+6=12-8x

<=>7x=1

 <=>x=\(\dfrac{1}{7}\)

vậy tập nghiệm S=\(\left\{\dfrac{1}{7}\right\}\)

Answer 4

a,5-(x-6)=4(3-2x)

<=>5-x+6=12-8x

<=>-x+8x=12-5-6

<=>7x=1

<=>x=1/7

Vậy ptr cho có tập No: S={1/7}