\(5\times\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{5}{5}+\dfrac{1}{5}=\dfrac{6}{5}\)
\(7:\dfrac{1}{5}+\dfrac{1}{5}=7\times5+\dfrac{1}{5}=35+\dfrac{1}{5}=\dfrac{175}{5}+\dfrac{1}{5}=\dfrac{176}{5}\)
\(6+\dfrac{1}{5}:2=6+\dfrac{1}{5}\times\dfrac{1}{2}=6+\dfrac{1}{10}=\dfrac{60}{10}+\dfrac{1}{10}=\dfrac{61}{10}\)
\(8-\dfrac{1}{5}\times7=8-\dfrac{7}{5}=\dfrac{40}{5}-\dfrac{7}{5}=\dfrac{33}{5}\)
a: =1+1/5=6/5
b: =35+1/5=35,2
c: =6+1/10=61/10
d: =8-7/5=33/5