`sqrt[ ( sqrt{5} -3)^2] + sqrt[(2+sqrt{5})^2]`
`= |sqrt{5} -3| + |2+sqrt{5}|`
`= 3 -sqrt{5} + 2+sqrt{5}`
`= 3+2 + (sqrt{5}-sqrt{5})`
`=5`
\(=3-\sqrt{5}+\sqrt{5}+2=5\)
`sqrt[ ( sqrt{5} -3)^2] + sqrt[(2+sqrt{5})^2]`
`= |sqrt{5} -3| + |2+sqrt{5}|`
`= 3 -sqrt{5} + 2+sqrt{5}`
`= 3+2 + (sqrt{5}-sqrt{5})`
`=5`
\(=3-\sqrt{5}+\sqrt{5}+2=5\)
\(x^3=\left(\sqrt[3]{5+2\sqrt{6}}+\sqrt[3]{5-2\sqrt{6}}\right)^3=\sqrt[3]{5+2\sqrt{6}}^3\)
\(+3\sqrt[3]{\left(5+2\sqrt{6}\right)^2}.\sqrt[3]{5-2\sqrt{6}}+3\sqrt[3]{5+2\sqrt{6}}.\sqrt[3]{\left(5-2\sqrt{6}\right)^2}+\sqrt[3]{5-2\sqrt{6}}^3\)
\(=5+2\sqrt{6}+3\sqrt[3]{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}.\sqrt[3]{5+2\sqrt{6}}\)
\(+3\sqrt[3]{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}.\sqrt[3]{5-2\sqrt{6}}+5-2\sqrt{6}\)
\(=5+5+3\sqrt[3]{\left(25-4.6\right)}.\sqrt[3]{5+2\sqrt{6}}+3\sqrt[3]{\left(25-4.6\right)}.\sqrt[3]{5-2\sqrt{6}}\)
\(=10+ 3\sqrt[3]{5+2\sqrt{6}}+3\sqrt[3]{5-2\sqrt{6}}\)
p/s : có bạn hỏi nên mình đăng , các bạn đừng report nhé
11) \(\dfrac{5+\sqrt{5}}{5-\sqrt{5}}\) + \(\dfrac{5-\sqrt{5}}{5+\sqrt{5}}\)
12) \(\dfrac{3+2\sqrt{3}}{\sqrt{3}}\) + \(\dfrac{2+\sqrt{2}}{\sqrt{2}+1}\) - \(\dfrac{1}{2-\sqrt{3}}\)
\(\)1) \(\dfrac{5+2\sqrt{5}}{\sqrt{5}+\sqrt{2}}\)
2) \(\dfrac{2\sqrt{6}-\sqrt{10}}{4\sqrt{3}-2\sqrt{5}}\)
3) \(\dfrac{1}{2\sqrt{2}-3\sqrt{3}}\)
4) \(\sqrt{\dfrac{3-\sqrt{5}}{3+\sqrt{5}}}\)
2+√5/√2+√3+√5 +2-√5/√2-√3-√5
rút gọn
g, \(\left(\dfrac{5-2\sqrt{5}}{2-\sqrt{5}}-2\right).\left(\dfrac{5+3\sqrt{5}}{3+\sqrt{5}}-2\right)\) h,\(\left(\dfrac{4}{3}\sqrt{3}+\sqrt{2}+\sqrt{3\dfrac{1}{3}}\right).\left(\sqrt{1,2}+\sqrt{2}-4\sqrt{\dfrac{1}{5}}\right)\)
Tính
a) \(\dfrac{2}{\sqrt{3}-\sqrt{5}}+\dfrac{3-2\sqrt{3}}{\sqrt{3}-2}\)
b) \(\dfrac{5-\sqrt{5}}{\sqrt{5}-1}+\dfrac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}\)
2+√5/√2+√(3+√5)+2-√5//√2-√(3+√5)
Q=(5-2 căn 5/2-căn 5 trừ 2 riêng).(5+3 căn 5/3+ căn 5 trừ 2 riêng)
h) |3x + 1|-x-5=0 i) 2x|x + 1] = 7 j) 7|2x + 1] = x 1 c) √5²-2 1 √5+2 + d) 5+2√5 3+√3 √5 + -√5-√3 √3+1
Toán số 9, liên quan đến dạng căn. Các bạn giúp mình nhé, xin cảm ơn rất nhiều. :)
1) (√3−2√√3−1+√3−1√2 )√√3−1
2) (√5+2√9√5−19−√7−√5):2√√5−2
3) √10+6√2−√10−6√2√5−√7 −√9+2√20
4) √5+√3+√5−√3√5+√22 −√6−√24√3+√3−√3−√3
5) √5+2√14√5−26−√4√5−1+√80−8√5
6) √11+√5+√11−√5√11+2√29 −√3−2√2