Question

4x+8/x^3+8 rút gọn

Answer 1

\(=\dfrac{4\left(x+2\right)}{\left(x+2\right)\left(x^2-2x+4x\right)}=\dfrac{4}{x^2-2x+4x}\)

Answer 2

\(\dfrac{4x+8}{x^3+8}=\dfrac{4\left(x+2\right)}{\left(x+2\right)\left(x^2-2x+4\right)}=\dfrac{4}{x^2-2x+4}\)