Question

4.(x+3)+2.(x-1)=16 

Answer 1

\(4\left(x+3\right)+2\left(x-1\right)=16\)

\(\Rightarrow4\cdot x+12+2\cdot x-2=16\)

\(\Rightarrow x\cdot\left(4+2\right)+\left(12-2\right)=16\)

\(\Rightarrow6\cdot x+10=16\)

\(\Rightarrow6\cdot x=16-10\)

\(\Rightarrow6\cdot x=6\)

\(\Rightarrow x=\dfrac{6}{6}\)

\(\Rightarrow x=1\)

Answer 2

\(4\left(x+3\right)+2\left(x-1\right)=16\)

\(4x+12+2x-2=16\)

\(6x=6\)

\(x=1\)