Question

(4x+3)²-4(x-1)²=0

 

Answer 1

\(\Leftrightarrow\left(4x+3\right)^2-\left(2x-2\right)^2=0\)

\(\Leftrightarrow\)\(\left(4x+3+2x-2\right)\left(4x+3-2x+2\right)=0\)

\(\Leftrightarrow\)\(\left(6x+1\right)\left(2x+5\right)=0\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=-\frac{1}{6}\\x=-\frac{5}{2}\end{cases}}\)

Answer 2

\(\Rightarrow x=\frac{-1}{6}\)

Answer 3

(4x+3)²-4(x-1)²=0

=>16x²+24x+9-4(x²-2x+1)=0

=>16x²+24x+9-4x²+8x-4=0

=>12x²+32x+5=0

=>12x²+30x+2x+5=0

=>6x(2x+5)+(2x+5)=0

=>(6x+1)(2x+5)=0

=>6x+1=0 hoặc 2x+5=0

=>x=-1/6 hoặc x=-5/2

vậy x=-1/6 hoặc x=-5/2