Question

4x³-4x²-x+1=0

 

Answer 1

\(\Leftrightarrow4x^2\left(x-1\right)-\left(x-1\right)=0\Leftrightarrow\left(2x-1\right)\left(2x+1\right)\left(x-1\right)=0\Leftrightarrow x=\dfrac{1}{2};x=-\dfrac{1}{2};x=1\)

Answer 2

\(4x^3-4x^2-x+1=0\)

<=>\(\left(2x+1\right)\left(x-1\right)\left(2x-1\right)=0\)

<=>\(\left[{}\begin{matrix}x=\dfrac{-1}{2}\\x=1\\x=\dfrac{1}{2}\end{matrix}\right.\)