\(4\left(x+3\right)\left(3x-2\right)-3\left(x-1\right)\left(4x-1\right)=-27\)
\(\Leftrightarrow\left(4x+12\right)\left(3x-2\right)-\left(3x-3\right)\left(4x-1\right)=-27\)
\(\Leftrightarrow12x^2+36x-8x-24-12x^2+12x+3x-3=-27\)
\(\Leftrightarrow43x=0\)
\(\Leftrightarrow x=0\)
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