`(4x+2)^2+(1-5x)^2-4(2x+1)(1-5x)=0`
`=> (4x+2)^2-4(2x+1)(1-5x)+(1-5x)^2=0`
`=> (4x+2-1+5x)^2=0`
`=> (9x+1)^2=0`
`=> 9x+1=0`
`=> 9x=-1`
`=> x= -1/9`
Vậy \(S=\left\{-\dfrac{1}{9}\right\}\)
Bài : Rút gọn
1) (3x - 5).(7-5x)-(5x+2).(2-3x)
2) (3x2+5x-2).(2x2-4x+3)
3) (3x2+5x-2).(2x2-4x+3)
4)4(2x3+x)-(2x-1)(4x2+3x+1)
5) 2x(x+3)-(x-5).(7+2x)
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Tìm x biết :
a, 4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6(x + 14)
b, 5.(3x + 5) - 4.(2x - 3) = 5x + 3.(2x + 12) + 1
c, 2.(5x - 8) - 3.(4x - 5) = 4.(3x - 4) + 11
d, (3x + 2)(2x + 9) - (x + 2)(6x + 1) = (x + 1) - (x - 6)
e, (8x - 3)(3x + 2) - (4x + 7)(x + 4)= (2x + 1)(5x - 1) - 33
Tìm x biết:
a) 4(18-5x) - 12(3x-7) = 15(2x-16) - 6(x+14)
b) 5(3x+5) - 4(2x-3) = 5x+3(2x+12)+1
c)2(5x-8) - 3(4x-5) = 4(3x-4) + 11
d) 5x-3 {4x-2 [4x-3(5x-2)]}=182
B1:tìm x biết a, (-2+x^2)(x^2-2)(x^2-2)(x^2-2)(x^2-2)=1 b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4) c,(8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1) d, 2x^2+3(x-1)(x+1)=5x(x+1) e, (8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x) f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
Bài 1:
a, (-2+x\(^2\))(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)=1
b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
c, (8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1)
d,2x\(^2\)+3(x-1)(x+1)=5x(x+1)
e,(8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x)
f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
a , | 4x + 2020 | = 0
b , | 2x + 1/4 | + | -5 | = | -14 |
c , | 2020 - 5x | - | 3 | = - | -8 |
d , | x mũ 2 + 4x | = 0
e , | x-1 | + 3x = 1
g , | 2-3x | + 3x = 2
h , | 5x-4 | + 5x = 4
i , | x - 1/4 | - | 2x + 5 | = 0
k , | 5x - 7 | - | 8-5x | = 0
n , | x mũ 3 - 4x | =0
Bài 1: Tìm nghiệm của các đa thức sau:
1, (x-4)2-(2x+1)2
2, x3 +x2-4x-4
3, x3+x2+4
4, 2x3 +5x2+5x+2
5, 6x4-5x3-38x2-5x+6
6, (8x+5)(4x+3)(2x+1)-9
7, (x-6)(x4)(x+1)(x-1)
8, (x+5)+(x+7)4-12
9, 3x4-7x2-10
10, (8x-7)(8x-5)(2x-1)(4x-1)-9
bài 1 Tim x a, 0,6x(x-0,5)-0,3x(2x+1,3)=0,138. , b, 3x2-3x(-2+x)=36. c, 2.(5x-8)-3(4x-5)=4(3x-4)+11 d, 1/3x2-4x+2x(2-3x)=0. e, 5x-3{4x-2(5x-2)]}=182 bài 2 thực hiện phép tính a, (-2x3-1/4y-4yz)8xy2 c,-6x+3(7+2x) e, 1/3xz(-9xy+15yz)+3x2(2yz2-yz)
