`<=>` \(\left[{}\begin{matrix}4x-9=0\\2,5-\dfrac{7}{2}x=0\end{matrix}\right.\)
`<=> \(\left[{}\begin{matrix}x=2,25\\x=\dfrac{5}{7}\end{matrix}\right.\)
\(\left(4x-9\right).\left(2,5+\dfrac{-7}{3}.x\right)=0\)
Tìm x :
1) \(\left(-0,75x+\dfrac{5}{2}\right).\dfrac{4}{7}-\left(-\dfrac{1}{3}\right)=-\dfrac{5}{6}\)
2) \(\left(4x-9\right)\left(2,5+\dfrac{-7}{3}x\right)=0\)
3) \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
4)\(\left(\dfrac{3}{5}-\dfrac{2}{3}x\right)^3=\dfrac{-64}{125}\)
a) (5x-1) . ( 2x-1/3)=0
b) ( -0,6x-1/2) .3/4-(-1)=1/3
c) ( 4x-9) ( 2,5+-7/3x)=0
d) 1/4x-1+1/3.(5/2x-6)-( 3/8x +)=4,5
Ai giúp mik với
Ai làm đầu đúng mình tích
b,(5/2-3X)=25/9
c,-5/6X+0,75=15/4
d,12/7-|x-1/3|=3/2
e,(x-1)mũ 5=-32
f,2 mũ x-3.2 mũ x=-8
g,9 mũ 5/3 mũ x=(-3) mũ 2
h,1/2x+3/5x=-33/25
k,(4x-9)(2,5+-7/3x)=0
Tìm x:
a) | 2x - 5 | + | 2,5 - x | = 0
b) | x - 1,5 | + | x + 3 | = 0
c) ( 5x - 2 )2 = 1
d) (4x - 1)3 + 7 = -20
a, 6,5 - 9/4 :| x + 1/3 |= 2
b, 11/4 + 3/2: | 4x - 1/ 5|= 7/2
c, 15/4 - 2,5 :| 3/4x + 1/2|= 3
Mn giúp mik vs mik đang cần gấp
Tìm x biết :
a, ( 4x - 9 ) . ( 2,5 + \(\frac{-7}{3}\). x ) = 0
b, \(\frac{1}{x\cdot\left(x+1\right)}\cdot\frac{1}{\left(x+1\right)\cdot\left(x+2\right)}\cdot\frac{1}{\left(x+2\right)\cdot\left(x+3\right)}-\frac{1}{x}=\frac{1}{2015}\)
Tìm x
(4x - 9) (2,5 + 2/3x)=0
(x - 5)2 = ( 1 - 3x)2
|x|=3
3| x+1| - 2=1
3|x + 1| + 2=1
(2/3x - 1/5) ( 3/5x+2/3) <0
| x - 2,5| - 3/4=0
| 3x + 7| = x- 9
Nếu 2x-7/4x-9=7/9; 3y -6 / 4z -8 = 3/ 4 và x ; y ;z khác 0 thì x / y + y /z
