Question

(4x-19)^4+(4x-20)^4=(39-8x)^4

Answer 1

Đặt 4x-19=a; 4x-20=b

Phương trình sẽ là \(a^4+b^4=\left(a+b\right)^4\)

=>\(-2ab\left(2a^2+3ab+2b^2\right)=0\)

\(\Leftrightarrow\left(4x-19\right)\left(4x-20\right)\left[2\left(4x-19\right)^2+3\left(4x-19\right)\left(4x-20\right)+2\left(4x-20\right)^2\right]=0\)

\(\Leftrightarrow\left(4x-19\right)\left(4x-20\right)=0\)

=>x=19/4 hoặc x=5