Question

(4x-1)^4=(4x-1)^2

ai giải giúp mk đc k ak, mk đang cần gấp nhé, thanks trc

Answer 1

+)=>(4x-1)^4:(4x-1)^2=1

=>(4x-1)^2=1

=>4x-1=1 hoặc 4x-1=-1

=>x=1/2 hoặc x=0

+)=>4x-1=0

=>x=1/4

Answer 2

\(\left(4x-1\right)^4=\left(4x-1\right)^2\)

\(\left(4x-1\right)^4\div\left(4x-1\right)^2=1\)

\(\left(4x-1\right)^2=1\)

\(\left(4x\right)^2-2.4x.1+1^2=1\)

\(16x^2-8x+1=1\)

\(16x^2-8x=0\)

\(8x\left(2x-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}8x=0\\2x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\2x=1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=0,5\end{cases}}}}\)