Question

(-4/7)^3 nhân (-4/7)^4 nhân (4/7)^5

Answer 1

Cho \(A=\left(-\dfrac{4}{7}\right)^3\times\left(-\dfrac{4}{7}\right)^4\times\left(\dfrac{4}{7}\right)^5\)

\(A=\left(-\dfrac{4}{7}\right)^{3+4}\times\left(\dfrac{4}{7}\right)^5\)

\(A=\left(-\dfrac{4}{7}\right)^7\times\left(\dfrac{4}{7}\right)^5\)

\(-A=-\left[\left(-\dfrac{4}{7}\right)^7\times\left(\dfrac{4}{7}\right)^5\right]\)

\(-A=\left(-\dfrac{4}{7}\right)^7\times\left(-\dfrac{4}{7}\right)^5\)

\(-A=\left(-\dfrac{4}{7}\right)^{7+5}\)

\(-A=\left(-\dfrac{4}{7}\right)^{12}\)

\(A=-\left(\dfrac{4}{7}\right)^{12}\)