\(-\dfrac{4}{3}:\left(x-\dfrac{1}{4}\right)^2=-\dfrac{3}{4}\)
\(\left(x-\dfrac{1}{4}\right)^2=\left(-\dfrac{4}{3}\right):\left(-\dfrac{3}{4}\right)\)
\(\left(x-\dfrac{1}{4}\right)^2=\left(-\dfrac{4}{3}\right).\left(-\dfrac{4}{3}\right)\)
\(\left(x-\dfrac{1}{4}\right)^2=\dfrac{16}{9}\)
\(\left[{}\begin{matrix}x-\dfrac{1}{4}=\dfrac{4}{3}\\x-\dfrac{1}{4}=-\dfrac{4}{3}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{19}{12}\\x=-\dfrac{13}{12}\end{matrix}\right.\)
Vậy...
-4/3:(x-1/4)^2=-3/4
(x-1/4)^2= -4/3 : (-3/4)
(x-1/4)^2= 16/9
x+1/4= 4/3 hoặc -4/3
TH1: x+1/4= 4/3
x=4/3-1/4
x=13/12
TH2: x+1/4= -4/3
x=-4/3-1/4
x=-19/12
Vậy x=13/12 hoặc x=-19/12
