\(\Leftrightarrow2x+1\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
hay \(x\in\left\{0;-1;1;-2;2;-3;7;-8\right\}\)
a , ( x + 7 ) : ( 2x - 1 )
b, ( 2x +7 ) : ( 2x -1 )
c, ( 3x + 9 ) : ( 2x + 3 )
d, ( 3x+ 8 ) : ( x - 2 )
(x2 + 9) (9x2 -1) = 0
(4x2 -9) (2x-1 -1) =0
( 3x+2) (9-x2 ) =0
(3x+3)2 ( 4x - 42 ) =0
2(x-5) ( x+2) =1
h/1/4-(2x+1/2)2=0
i/25.(3x-1/2)2=16
k/3.(3x-1/2)3+1/9=0
m/x+1/3=3/9
(x+2).(2x-1)=0
(3x-+9).(1-3x)=0
tìm X
1/4+2.(3.x-2/3)=1
(1/2+2X). (2x-3)=0
(4x-5).(5/4.x-2)=0
1/9-(2.x+1/2)mũ 2=0
9.(3x-1/2)mũ 2 =4
1/2.x+2/3.x-1=-10/3
X+1/12=-3/9
|3x+1|=2x-9
3x - 2x=13-19
3x+7=4-3x
5 (×+1)-3×=×+9
giải hộ mình vs, mình đang cần gấp
a)-2.(15-3x)-4.(-7x+8)-5-9.(-2x+1)
b)5.(-3x-7)-4.(-2x-11)=7.(4x+10)+9
/3x+2/+/10+3x/=8
/9-x/+/x+5/=12
/2x+1/+/x-y/+/2x-9/=10
Tìm x,y
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