Question

3x^2 + 6xy - 48 + 3y^2

Answer 1

\(3x^2+6xy-48+3y^2=3\left[\left(x^2+2xy+y^2\right)-16\right]=3\left[\left(x+y\right)^2-16\right]=3\left(x+y-4\right)\left(x+y+4\right)\)

Answer 2

\(3x^2+6xy-48+3y^2\)

\(=3\left(x^2+2xy+y^2-16\right)\)

\(=3\left(x+y+4\right)\left(x+y-4\right)\)