MỌI NGƯỜI GIÚP EM VỚI
Bài 1: tìm x
a)\(\left|3x-5\right|=4\)
b)\(\dfrac{x+1}{10}+\dfrac{x+1}{11}+\dfrac{x+1}{12}=\dfrac{x+1}{13}+\dfrac{x+1}{14}\)
c)\(\dfrac{x+4}{2000}+\dfrac{x+3}{2001}=\dfrac{x+2}{2002}+\dfrac{x+1}{2003}\)
Bài 2: Tính
a)\(\dfrac{\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}}{\dfrac{4}{9}-\dfrac{4}{7}-\dfrac{4}{11}}+\dfrac{\dfrac{3}{5}-\dfrac{3}{25}-\dfrac{3}{125}-\dfrac{3}{625}}{\dfrac{4}{5}-\dfrac{4}{25}-\dfrac{4}{125}-\dfrac{4}{625}}\)
b)\(\dfrac{1}{100.99}-\dfrac{1}{99.98}-\dfrac{1}{98.97}-...-\dfrac{1}{3.2}-\dfrac{1}{2.1}\)
c)\(\dfrac{\left(\dfrac{3}{10}-\dfrac{4}{15}-\dfrac{7}{20}\right).\dfrac{5}{19}}{\left(\dfrac{1}{14}+\dfrac{1}{7}-\dfrac{-3}{35}\right).\dfrac{-4}{3}}\)
Tìm x:
x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14
x+4/2000 + x+3/2001 = x+2/2002 + x+1/2003
TFM SỐ HỮU TỶ X:
a) X+1/10 + X+1/11 + X+1/12 =X+1/13 + X+1/14
b) X+4/2000 + X+3/2001 = X+2/2002+ X+1/2003
Tìm x, biết :
a) x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14
b) x+3/2000 + x+3/2001 = x+2/2002 + x+2/2003
1:x+4/2000+ x+3/2001= x+2/2002+ x+1/2003
2:7x(X-1)+2Xx(1-X)=0
3:11/12-(2/5+x)=2/3
4:A=3x+8xy+3y với x+y=4/3, x.y=-2
. là nhân
thực hiện phép tính:
a)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
b)\(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
Tìm số hữu tỉ x , biết rằng
e,\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
f, \(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
Tìm x
a)x+2x+3x+4x+...+100x=-213
b)x+1/3=x-2/4
c)x-6/7+x-7/8+x-8/9=x-9/10+x-10/11
d)x+32/11+x+23/12=x+38/13+x+27/14
e)x-1/2004+x-2/2003-x-3/2002+x-4/2001
GIẢI GIÚP MÌNH NHA MÌNH ĐANG CẦN GẤP
Tìm số hữu tỉ x, biết:
a) \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}+\frac{x+1}{13}+\frac{x+1}{14}\)
b) \(\frac{x+4}{2000}+\frac{x+3}{2001}+\frac{x+2}{2002}+\frac{x+1}{2003}\)