Question

(3x - 2)(x^2 + 16) = (2x - 7)(x^2 + 16) giúp với ạ

Answer 1

\(\left(3x-2\right)\left(x^2+16\right)=\left(2x-7\right)\left(x^2+16\right)\)

\(\Leftrightarrow\left(3x-2\right)\left(x^2+16\right)-\left(2x-7\right)\left(x^2+16\right)=0\)

\(\Leftrightarrow\left(x^2+16\right)\left(3x-2-2x+7\right)=0\)

\(\Leftrightarrow\left(x^2+16\right)\left(x+5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x^2+16=0\\x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\pm\sqrt{-16}\\x=-5\end{matrix}\right.\)

Answer 2

=>3x-2=2x-7

=>x=-5

Answer 3

\(\left(3\text{x}-2\right)\left(x^2+16\right)=\left(2\text{x}-7\right)\left(x^2+16\right)\)

\(\Leftrightarrow\left(3\text{x}-2\right)=\left(2\text{x}-7\right)\)

\(\Leftrightarrow3\text{x}-2x=-7+2\)

\(\Leftrightarrow x=-5\)