Lời giải:
\(-3x-\frac{2}{3}=\frac{-6}{7}-x\)
\(-3x+x=\frac{-6}{7}+\frac{2}{3}\)
\(-2x=\frac{-4}{21}\Rightarrow x=\frac{2}{21}\)
Ta có: \(-3x-\dfrac{2}{3}=-\dfrac{6}{7}-x\)
\(\Leftrightarrow-3x+x=\dfrac{-6}{7}+\dfrac{2}{3}=-\dfrac{4}{21}\)
hay \(x=\dfrac{2}{21}\)