\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(\left(3x-\frac{3}{2}\right)-\left(5x+3\right)=-x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3-\frac{1}{5}=-x\)
\(-2x-6,7=-x\)
\(-2x-x=6,7\)
\(-3x=6,7\)
\(x=-\frac{67}{30}\)
Vậy \(x=-\frac{67}{30}\)
=>3x-3/2-5x-3=-x+1/5
=>-2x+x=1/5+9/2
=>-x=47/10
=>x=-47/10