\(\dfrac{3}{5}x-\dfrac{1}{2}=\dfrac{3}{7}\)
\(\Leftrightarrow\dfrac{3}{5}x=\dfrac{3}{7}+\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{3}{5}x=\dfrac{13}{14}\)
\(\Leftrightarrow x=\dfrac{13}{14}:\dfrac{3}{5}\)
\(\Leftrightarrow x=\dfrac{13}{14}\cdot\dfrac{5}{3}\)
\(\Leftrightarrow x=\dfrac{65}{42}\)
Vậy \(x=\dfrac{65}{42}\)
\(\dfrac{3}{5x}-\dfrac{1}{2}=\dfrac{3}{7}\) (ĐKXĐ: \(x\ne0\))
\(\Leftrightarrow\dfrac{3}{5x}=\dfrac{13}{14}\)
\(\Rightarrow65x=42\)
\(\Leftrightarrow x=\dfrac{42}{65}\)
Vậy \(x=\dfrac{42}{65}\)
\(\dfrac{3}{5}x-\dfrac{1}{2}=\dfrac{3}{7}\)
\(\Rightarrow\dfrac{3}{5}x=\dfrac{3}{7}+\dfrac{1}{2}=\dfrac{13}{14}\Rightarrow x=\dfrac{13}{14}:\dfrac{3}{5}=\dfrac{65}{42}\)
