\(\dfrac{-3}{4x+2}< 0\)
\(\Leftrightarrow4x+2< 0\)
hay \(x< -\dfrac{1}{2}\)
\(\dfrac{-3}{4x+2}< 0\Leftrightarrow4x+2>0\left(-3< 0\right)\Leftrightarrow x>-\dfrac{1}{2}\)
2.(3/4x-1)-3y(1-3/4x)=0
tim x:
a, 3(2x+3)(3x-5)<0
b, 2x2 - 4x>0
c, 5(3x+1)(4x-3)>0
tìm x biết:
x^2-4x=0
4x-(3+5x)=14
-7^5.3^3/ 7^2.(-3)^3
1) (3x-6)(x+5)+4(x-2)=0
2) 3(x-5)(2x+9)+3x-15=0
3) (x2-16)(12-4x)=0
4) (9-x2)(4x-8)=0
5) (8-x3)(5x-125)=0
6) 4x=8
a/ 2.(1/2x -1/3)-3/2=1/4
b/ (1/2+2x)(2x-3)=0
c/ (4x-5)(5/4x-2)=0
d/ 1/4-(2x+1/2)mũ hai=0
Bài 1 : Tìm số nguyên x , biết :
a, x . ( x + 7 ) = 0
b, ( 2 + 2x ) . ( 7 - x ) = 0
c, x^3 - 4x = 0
d, ( x^2 - 9 ) . ( 3x + 15 ) = 0
e, ( 4x - 8 ) . ( x^2 + 1 ) = 0
x^2+2x=0
x^3-4x=0
3x+4x chia hết cho x+1
(2x+1).(y-3)= -10
1,-15(x+2)+7(2x-3)
2,x^2+2x=0
3,(-2x)(-4x)+28=100
4,(2x-5)^2-49=0
5,/x-5/+/y-3/=1
6,3×(x-2)-6(x-5)=2(5-2x)
7, 5x ×(-x)^2+1=0
8,4x^3=4x
Bài 1: Tìm x biết :
a) (x+2)^2 - (3x-7)^2=0
b) (4x+1) -(5x-3)^2=0
c) 25(x-3)^2 - 49(2x+1)^2=0
d) 9(3x-2)^2=121(1-4x)^2
e) (x-5/4)^2=(5x+1/2)^2
