= (3/4-81)....(3^6/9 - 81)....(3^2000/2003 - 81)
= 0
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Các câu hỏi tương tự
Tính
a)\((\dfrac{3}{4}-81).(\dfrac{3^2}{5}-81).(\dfrac{3^3}{6}-81)...(\dfrac{3^{2000}}{2003}-81)\)
b)\(\dfrac{69}{157}-(2+(3+(4+5^{-1})^{-1})^{-1}\)
Tính:
\(\left(\dfrac{3}{4}-81\right).\left(\dfrac{3^2}{5}-81\right).\left(\dfrac{3^3}{6}-81\right).....\left(\dfrac{3^{2000}}{2003}-81\right)\)
Tính: \(A=\frac{3}{4-81}.\frac{3^2}{5-81}.\frac{3^3}{6-81}...\frac{3^{2000}}{2003-81}\)
Tính: \(\left(\frac{3}{4}-81\right)\left(\frac{3^2}{5}-81\right)\left(\frac{3^3}{6}-81\right)...\left(\frac{3^{2000}}{2003}-81\right)\)
Tính (3/4-81)(3^5/81)...(3^2000/2003-81)
Tính:
\(\left(\frac{3}{4}-81\right).\left(\frac{3^2}{5}-81\right).\left(\frac{3^3}{6}-81\right)...\left(\frac{3^{2000}}{2003}-81\right)\)
Giup mik với tính (3/4-81)(32/5-81)(33/6-81).....(32000/2003-81)
10 tích đó
A=\(\left(\frac{3}{4}-81\right)\left(\frac{3^2}{5}-81\right)\left(\frac{3^3}{6}-81\right)...\left(\frac{3^{2000}}{2003}-81\right)\)
hỏi A bằng bao nhiêu
Tính (3/4-81)(3^2/5)...(3^2000/2003-81)