\(\Leftrightarrow2x+1=4\\ \Leftrightarrow x=\dfrac{3}{2}\)
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\(\Leftrightarrow2x+1=4\\ \Leftrightarrow x=\dfrac{3}{2}\)
32x+1=81
Tìm x
81/(3^2x+1)=3
(1/3)^2x-1 - (1/3)^2 = -2/27
3^7-3x = 81
3^2x+1=81
Tìm x: 3^2x+1= 81
Tìm x biết (-3/5)^2x-1=-81/625
3^2x=81
3 (x-4)+3=x+1
/
\(\frac{81}{3^{\left(2x+1\right)}}=3\)
tìm x biết
(1/2) mũ 2x-1 = 1/8
(-1/3)x-3= 1/81