\(\Leftrightarrow2x+1=3\)
hay x=1
\(\left(2x+1\right)^3=27\)
\(\left(2x+1\right)=3\)
\(2x=2\)
\(x=1\)
Vậy \(x=1\)
(2x+1)3 =81:3
(2x+1)3 = 27
(2x+1)3 = 33
=>2x+1=3
2x=4
=>x=2
nhớ tick cho anh nha
Em tham khảo cách làm:
\(3\left(2x+1\right)^3=81\\ \left(2x+1\right)^3=81:3\\ \left(2x+1\right)^3=27\\ =>\left(2x+1\right)^3=3^3\\ =>2x+1=3\\ 2x=3-1\\ 2x=2\\ x=2:2\\ x=1\)