Question

3.2^1+x - 5=19cứuuu

Answer 1

`3 . 2^(1+x) - 5 = 19`

`=> 3 . 2^(1 + x) = 19 + 5`

`=> 3 . 2^(1 + x) = 24`

`=> 2^(1 + x)=24:3`

`=> 2^(1+x)=8`

`=> 2^(1+x) = 2^3`

`=>1+x=3`

`=>x=3-1`

`=>x=2`

Vậy: `x=2`

Answer 2

`3 xx 2^(x +1) -5= 19`

`=>3 xx 2^(x + 1) = 19 +5`

`=>3xx 2^(x +1) = 24`

`=>      2^(x + 1) = 24 : 3`

`=>    2^(x + 1) = 8`

`=> 2^(x + 1) = 2^3`

`=> x + 1 = 3`

`=> x = 3-1`

`=> x = 2`

Vậy `x = 2`

Answer 3

\(3.2^{1+x}-5=19\)

\(3.2^{1+x}=19+5\)

\(3.2^{1+x}=24\)

\(2^{1+x}=24:3\)

\(2^{1+x}=8\)

\(2^{1+x}=2^3\)

\(1+x=3\)

\(x=3-1\)

\(x=2\)